这段代码展示了如何将用户输入的文本分割成两个或多个字符串。如果您正在制作应用程序或游戏，并且希望用户输入类似“装备剑”之类的内容，这将非常有用。此应用程序将单词分割成两个单词，“装备”和“剑”，您可以检查动作“装备”并执行某些操作，例如在本例中它将装备一把剑。
分割两个字符串
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#include <iostream>
using namespace std;
#define NUM 20
inline void splitString(char c[])
{
//These are used to hold the temporary words like "equip" or "sword"
char tempchar1[NUM] = " ";
char tempchar2[NUM] = " ";
//This checks through the whole text typed until it reaches a space
for(int i = 0; i < NUM;i++)
{
//Assigns the first word to the tempchar1
tempchar1[i] = c[i];
//Checks if it has reached a space
if(c[i + 1] == ' ')
{
//Used to assign the second word to tempchar2
for(int r = i + 2;r < NUM;r++)
{
tempchar2[r - (i + 2)] = c[r];
}
i = NUM;
}
}
//Prints the two characters
cout << "tempchar1 = \"" << tempchar1 << "\"" << endl <<
"tempchar2 = \"" << tempchar2 << "\"" << endl;
}
int main()
{
char Char[NUM];
cin.getline(Char, NUM);
splitString(Char);
system("pause");
return 0;
}
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如果您想拥有多个项目，您可以这样做
分割三个字符串
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#include <iostream>
using namespace std;
#define NUM 20
inline void splitString(char c[])
{
char tempchar1[NUM] = " ";
char tempchar2[NUM] = " ";
char tempchar3[NUM] = " ";
for(int i = 0; i < NUM;i++)
{
tempchar1[i] = c[i];
if(c[i + 1] == ' ')
{
for(int r = i + 2;r < NUM;r++)
{
tempchar2[r - (i + 2)] = c[r];
if(c[r + 1] == ' ')
{
for(int q = r + 2; q < NUM;q++)
{
tempchar3[q - (r + 2)] = c[q];
}
r = NUM;
}
}
i = NUM;
}
}
cout << "tempchar1 = \"" << tempchar1 << "\"" << endl <<
"tempchar2 = \"" << tempchar2 << "\"" << endl <<
"tempchar3 = \"" << tempchar3 << "\"" << endl;
}
int main()
{
char Char[NUM];
cin.getline(Char, NUM);
splitString(Char);
system("pause");
return 0;
}
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输出结果可能如下 -
在创建基于文字的游戏，并且您希望他们输入咒语然后输入目标或其他类似的内容时，这非常有用。 有了它，就有无限的可能性。
这是一个如何使用此独特功能的示例程序 -
示例
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#include <iostream>
#include <string>
using namespace std;
#define CHAR 30
//Prototypes
void getUserI();
int main();
void catchErrors(char error[CHAR]);
//Convention - c infront of a name = current
int maxhp = 100, pHp = maxhp;
int maxmana = 100, cmana = maxmana;
int playerChoice, numWeapsInInventory = 3;
string tagWeap = "";
int lvl = 12, strength = 1, intelligence = 3, dexterity = 8, agility = 4, maxWeapons = 3;
string cweapon = "Fist", playerJob = "Farmer", playerName = "Demon Slayer";
bool exitGame = false;
void showStat()
{
system("cls");
cout << "\tName : " << playerName << "\n\nWeapon : " << cweapon << "\n\n" << "\tJob : " << playerJob << "\n";
cout << "\tLvl : " << lvl << "\n\tHealth : " << pHp << "/" << maxhp << "\n";
cout << "\tMana : " << cmana << "/" << maxmana << "\n\n";
cout << "Strength : " << strength << "\n" << "Intelligence : " << intelligence << "\n";
cout << "Dexterity : " << dexterity << "\n" << "Agility : " << agility << "\n\n";
}
void catchErrors(int error)
{
switch(error)
{
case 1:
cout << "You did not type an action, please try again" << endl;
break;
default:
cout << "ERROR in catchErrors. You should not see this!!" << endl;
break;
}
getUserI();
}
void decipherChar(char c[CHAR])
{
//Temporary holding characters to hold the action and another variable needed to split
char tempchar[CHAR] = " ";
char tempchar2[CHAR] = " ";
//Checks the char c letter by letter
for(int i = 0; i < CHAR; i++)
{
//Assigns the letters one by one to the tempchar
tempchar[i] = tolower(c[i]);
//Checks if it has reached a space or the null character - used for just actions etc exit
if(c[i + 1] == ' ' || c[i + 1] == '\0')
{
// equip
if(tempchar[0] == 'e' && tempchar[1] == 'q' && tempchar[2] == 'u' && tempchar[3] == 'i' && tempchar[4] == 'p')
{
//Goes through the second part of the string
for(int w = 6;w < CHAR; w++)
{
//Makes sure that it wont add any weird characters for the other 20 or so elements of the array
if(c[w] != '\0')
{
//Assigns the first array in tempchar2 to the weapon
tempchar2[w - 6] = tolower(c[w]);
}
else break;
}
cout << "You eqipped " << tempchar2 << endl;
//Assigns the weapon
cweapon = tempchar2;
}
// stat
else if(tempchar[0] == 's' && tempchar[1] == 't' && tempchar[2] == 'a' && tempchar[3] == 't')
{
showStat();
}
// exit
else if(tempchar[0] == 'e' && tempchar[1] == 'x' && tempchar[2] == 'i' && tempchar[3] == 't')
{
exitGame = true;
main();
}
else
{
catchErrors(1);
}
//sets i to char so the for loop ends
i = CHAR;
}
}
//Goes back to asking the user another choice
getUserI();
}
void getUserI()
{
char choice[CHAR];
//Gets the whole line that the user has typed in including spaces and everything
cin.getline(choice, CHAR);
decipherChar(choice);
}
int main()
{
if( exitGame != true)
{
getUserI();
}
system("pause");
return 0;
}
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顺便说一下，退出功能无法正常工作，并且某些变量可能未使用，但这是一个关于如何将此功能集成到您的程序中的示例。 可能有更好的方法，我可能会在其他时间发布，也许使用类，但这种方法目前来说非常好。 祝你玩得开心。
Sean Genge
